ClassesClass 9MathsNCERTLinear PolynomialsExercise 2.4Q 2
QUESTION 2 ii Easy

A mobile phone is bought for ₹10000. Its value decreases by ₹800 every year. Make a table of values for t varying from 0 to 8 years and show how the value of the phone, v, depreciates with time.

SOLUTION

t (years) v (value of phone)
010000
19200
28400
37600
46800
56000
65200
74400
83600
This represents linear decay as phone's value decreases by the same amount(₹800) each year.
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Final Answer : Value decreases by constant ₹800 each year.

Concept Note

The linear decay is given by the formula
\(v = v_{0} + (r × t)\),
where
\(v_0 = \) initial value
\(r = \) constant annual decrease
\(t = \) time in years
Every year the phone loses the same value, making it easy to calculate future values.