QUESTION 2
ii
Easy
A mobile phone is bought for ₹10000. Its value decreases by ₹800 every year. Make a table of values for t varying from 0 to 8 years and show how the value of the phone, v, depreciates with time.
SOLUTION
| t (years) | v (value of phone) |
|---|---|
| 0 | 10000 |
| 1 | 9200 |
| 2 | 8400 |
| 3 | 7600 |
| 4 | 6800 |
| 5 | 6000 |
| 6 | 5200 |
| 7 | 4400 |
| 8 | 3600 |
🏆
Final Answer : Value decreases by constant ₹800 each year.
Concept Note
The linear decay is given by the formula
\(v = v_{0} + (r × t)\),
where
\(v_0 = \) initial value
\(r = \) constant annual decrease
\(t = \) time in years
Every year the phone loses the same value, making it easy to calculate future values.