QUESTION 7
i
Easy
Draw the graph of the following equations, and identify their slopes and y-intercepts. Also, find the coordinates of the points where these lines cut the y-axis.
y = −3x + 4
SOLUTION
1
Find slope and y-intercept from the given equation
\(y = −3x + 4\)
Here, slope \(= −3\) and \(y-\)intercept \(= 4 \)
The line cuts \(y-\)axis at (\(0,4\)).
Here, slope \(= −3\) and \(y-\)intercept \(= 4 \)
The line cuts \(y-\)axis at (\(0,4\)).
2
Find two points on the line to draw the graph
When \(x = 1 , y = 1\)
So the point is (\(1,1\)).
When \(x = 2, y = −2\)
So the point is (\(2,−2\)).
So the point is (\(1,1\)).
When \(x = 2, y = −2\)
So the point is (\(2,−2\)).
🏆
Final Answer : slope \(= −3\), \( y-\)intercept \(= 4 \) and the line cuts \(y-\)axis at (\(0,4\)).
Concept Note
The equation of a straight line is of the form
\(y = mx + c\), where
\(m = \)slope
\(c = \)y-intercept
The values \(m\) and \(c\) completely describe the line's direction, steepness and position.