ClassesClass 9MathsNCERTPerimeter and AreaExercise 6.2Q 4
QUESTION 4 Easy

The sides of a triangular plot are in the ratio 3 : 5 : 7; its perimeter is 300m. Find its area.

SOLUTION

1
Find the actual sides
Given ratio is 3 : 5: 7
Total parts : 3+5+7 = 15
Perimeter = 300 m
One part : \(\frac{300}{15} \,=\,20\,m\)
Therefore,
First side : \(3 × 20\,= \,60\,m\)
Second side : \(5 × 20\,=\,100\,m\)
Third side : \(7 × 20\,=\,140\,m\)
2
Find the semi-perimeter
\(s = \frac{300}{2}\,=\,150\,m\)
3
Apply Heron's Formula
\(\begin{aligned}Area &= \sqrt{150(150−60)(150−100)(150−140)} \\ &= \sqrt{150 × 90 × 50 × 10} \\ &= \sqrt{6750000} \\ &= \sqrt{675 × 10000} \\ &= 100 \sqrt{675} \\ &= 100 \sqrt{15^2 × 3} \\ &= 100 × 15 \sqrt{3} \\ &= 1500 \sqrt{3}\end{aligned}\)
Using √3 ≈ 1.732,
\(Area ≈ 1500 × 1.732\,=\,2598\,m^2\)
The area is 1500√3 or 2598 m\(^2\).
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Final Answer : The area is 1500√3 or 2598 m\(^2\).

Concept Note

When the sides of a triangle are given in a ratio and the perimeter is known:
1. Find the actual lengths of the sides.
2. Find the semi-perimeter.
3. Apply Heron's formula.