Find the first five terms of the sequence in which the \(n^{th}\) term is given by \(t_n = 3n − 4\) for \(n ≥ 1\).

The first five terms are obtained by substituting \(n = 1, 2, 3, 4, 5\).
\(t_1 = 3(1) − 4 = −1\)
\(t_2 = 3(2) − 4 = 2\)
\(t_3 = 3(3) − 4 = 5\)
\(t_4 = 3(4) − 4 = 8\)
\(t_5 = 3(5) − 4 = 11\)
The first five terms are: \(−1, 2, 5, 8, 11\)