QUESTION 1
ii
Easy
Find the first five terms of the sequence in which the \(n^{th}\) term is given by \(t_n = 2 − 5n\) for \(n ≥ 1\).
SOLUTION
The first five terms are obtained by substituting \(n = 1, 2, 3, 4, 5\).
\(t_1 = 2 − 5(1) = −3\)
\(t_2 = 2 − 5(2) = −8\)
\(t_3 = 2 − 5(3) = −13\)
\(t_4 = 2 − 5(4) = −18\)
\(t_5 = 2 − 5(5) = −23\)
The first five terms are: \(−3, −8, −13, −18, −23\)
\(t_1 = 2 − 5(1) = −3\)
\(t_2 = 2 − 5(2) = −8\)
\(t_3 = 2 − 5(3) = −13\)
\(t_4 = 2 − 5(4) = −18\)
\(t_5 = 2 − 5(5) = −23\)
The first five terms are: \(−3, −8, −13, −18, −23\)
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Final Answer : −3, −8, −13, −18, −23
Concept Note
To find the terms in a sequence, simply substitute the values of \(n\).