Find the first five terms of the sequence in which the \(n^{th}\) term is given by \(t_n = n^2 − 2n + 3\) for \(n ≥ 1\).

The first five terms are obtained by substituting \(n = 1, 2, 3, 4, 5\).
\(t_1 = 1^2 − 2(1) + 3 = 2\)
\(t_2 = 2^2 − 2(2) + 3 = 3\)
\(t_3 = 3^2 − 2(3) + 3 = 6\)
\(t_4 = 4^2 − 2(4) + 3 = 11\)
\(t_5 = 5^2 − 2(5) + 3 = 18\)
The first five terms are: \(2, 3, 6, 11, 18\)