ClassesClass 9MathsNCERTSequences and ProgressionsExercise 8.1Q 2
QUESTION 2 Easy

Find the \(10^{th}\) and \(15^{th}\) terms of the sequence \(t_n = 5n − 3\) for \(n ≥ 1\).

SOLUTION

1
Find the \(10^{th}\) term
\(\begin{aligned} t_10 &= 5(10) −3)\\ &= 50 − 3 \\ &= 47\end{aligned}\)
The \(10^{th}\) term is 47.
2
Find the \(15^{th}\) term
\(\begin{aligned} t_15 &= 5(15) −3)\\ &= 75 − 3 \\ &= 72\end{aligned}\)
The \(15^{th}\) term is 72.
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Final Answer : \(10^{th}\) term: 47
\(15^{th}\) term: 72

Concept Note

To find the term in a given sequence, simply substitute the value of \(n\).