QUESTION 4
Easy
Which term of the sequence \(t_n = 5n − 3\) for \(n ≥ 1\) is 607?
SOLUTION
Set \(5n − 3 = 607\)
⇒\(5n = 610\)
⇒\(n = 122\)
Therefore, 607 is the \(122^{nd}\) term.
⇒\(5n = 610\)
⇒\(n = 122\)
Therefore, 607 is the \(122^{nd}\) term.
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Final Answer : 607 is the \(122^{nd}\) term.
Concept Note
Set the general term equal to the given value and solve for \(n\). The value of \(n\) gives the term number.